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An Antacid Tablet Containing 0.50 G Of Nahco3 Is Dissolved In 250 Ml Of Water. What Is The Molar Concentration Of Nahco3 In The Solution? *
An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution? * Molar concentration is solved by determining the molar mass by dividing the amount of solutes to the volume of solution then dividing it to 0.5g. You also need to convert the amount of solutes from grams into moles, and the volume of solution from ml into L In solving the moles of solute, note the NaHCO3, it has 1 Sodium atom, 1 hydrogen atom, 1 carbon atom and 3 oxygen atom. Find its atomic mass according to the periodic table Na=22.99 H=1.008 C= 12.01 O=16.0 Multiply the quantities and add... Atomic mass of NaHCO3= 22.99+1.008+12.01+(16.0×3) =22.99+1.008+12.01+ 48 =84.008 g/ mol Divide it to 0.5 g =0.5g÷ 84.008g/mol =5.951814113^-3 mol Now convert ml to L 250÷1000= 0.25L C=n/v C= =5.951814113^-3 mol/0.25L C= 0.023807256 mol/L or 0.024 mol/L
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